Integration Problem: Solving $\int_{0}^{\infty}x^3.e^{-x^2}\mathrm{d}x$

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Homework Statement



\int_{0}^{\infty}x^3.e^{-x^2} \mathrm{d}x

The Attempt at a Solution



I have tried substitution u=x^2, u=x^3; integration by parts; squeeze theorem; partial fraction decomp; taylor series expansion- but nothing seems to work. I know the limit of x^3.e^{-x^2} as x tends to infinity is zero, but that doesn't help.
Any help please?
 
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qspeechc said:
I have tried substitution u=x^2
That should work.
 
Well, ok.

Let u = x^2 , then: du = 2x.dx. And then what? We have an x^3 in the integration, so I don't see how it works.
 
But x3 = x.x2, isn't it?
 
Yes, but then we would have:

x^2.e^{-u}.du or am I missing something?
 
qspeechc said:
x^2.e^{-u}.du or am I missing something?
You just did the sub u=x^2 a couple of steps ago.
 
AHA! Oh thank-you neutrino! I can't believe I never saw that! Gee, I feel like an idiot! Thank-you again!
 
qspeechc said:
AHA! Oh thank-you neutrino! I can't believe I never saw that! Gee, I feel like an idiot! Thank-you again!

You're welcome. Make a hobby out of solving integrals (if you're into those kind of things), and you'll start recognising the methods with just a look at the integral. (For some of them, at least. :biggrin:)
 
Actually I quite dislike calculus. I find it dry and boring. Or atleast that's the way my first year course presents it. But I guess you are right, I need to do more calculus problems if I want to be a mathematician :-p, which I do.
 
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