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Intensity - Double slit diffraction

  1. Oct 2, 2012 #1
    Hello. I have been studying interference and diffraction and one doubt has appeared. When you consider the double slit experiment forgeting the effects of diffraction you get the following equation for intensity

    [itex]I^{}=4I_{0}cos^{2}(\frac{πdsin(θ)}{λ})[/itex]

    where d is the distance between the slits.
    For the single slit diffraction we get

    [itex]I^{}=I_{0}(\frac{sin(x)}{x})^{2}[/itex]

    [itex]x^{}=(\frac{asinθπ}{λ})[/itex]

    where a is the width of the slit.

    Then for the double-slit case considering diffraction we get

    [itex]I^{}=4I_{0}cos^{2}(\frac{πdsin(θ)}{λ})(\frac{sin(x)}{x})^{2}[/itex]

    My doubt raises when i consider the two limit cases:
    1.For a/λ going to 0 the expression becomes that of the interference-only case.
    2.But when we consider d=0(the distance between the centers of the slits) the expression obtained is

    [itex]I^{}=4I_{0}(\frac{sin(x)}{x})^{2}[/itex]

    which is different from that of the single slit case although doing d=0 we are turning two slits of width a in one slit of width a.

    My thoughts trying to solve this problem have considered that maybe i am taking the limit case wrong (although i havent found where) or some expression for the intensity is wrong.

    Thanks in advance for your attention, expecting a good answer...

    PS.:I also apologize in advance for any mistake in my english writing...Brazilian here.
     
    Last edited: Oct 3, 2012
  2. jcsd
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