Intensity for circular polarised light through linear polariser

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When circularly polarized light passes through a linear polarizer, the intensity is reduced by half, as the polarizer treats circularly polarized light similarly to unpolarized light. In the first scenario described, after the initial vertical linear polarizer, the quarter wave plate converts the light to circular polarization, but the subsequent horizontal polarizer will indeed decrease the intensity again. In the second scenario, starting with a 45° linear polarizer, the quarter wave plate does not affect the polarization significantly, leading to complete absorption by the second -45° polarizer. Thus, the first flow results in a non-zero intensity while the second flow results in zero intensity. The discussion confirms the behavior of polarizers and quarter wave plates in these contexts.
dalind
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Hi,

does the intensity change when circularly polarised light passes through a linear polariser?
I am thinking of a flow like this: natural light -> vertical linear polariser -> quarter wave plate -> horizontal linear polariser -> intensity?

After the first polariser, the intensity is 50%, the quarter wave plate changes the linear polarisation to circular. But does the horizontal linear polariser decrease the intensity again?

Edit: Another flow would be natural light -> 45° linear polariser -> quarter wave plate -> - 45° linear polariser -> intensity? Since I think the polarisation is not affected by the quarter wave plate if the light is polarised vertically, I think the first flow would result in a complete absorption of the light by the second polariser (Intensity 0), right?

Thank you.

Cheers,
dalind
 
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Yes, the second polariser cuts the intensity of the circular light in half.
 
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... and makes it linearly polarized.
A plane polarizer treats circularly polarized light the same as it treats unpolarized light.
 
Okay, thanks. That's what I thought. And this only works for the second flow I described, for the first one the quarter-wave plate would not change the polarization and would therefore practically be useless, right?
 

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