Intensity of sounds - Hearing Aid

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SUMMARY

A hearing aid increases sound intensity by 50 dB, which corresponds to an increase of 100,000 times in intensity. The relationship between intensity and amplitude is defined by the equation Intensity ∝ (Amplitude)^2. Therefore, to determine the increase in amplitude, one must take the square root of the intensity increase, resulting in an amplitude increase of 316.23 times.

PREREQUISITES
  • Understanding of decibels (dB) and sound intensity
  • Knowledge of the relationship between intensity and amplitude
  • Familiarity with basic acoustic principles
  • Mathematical skills for square root calculations
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  • Research the formula for sound intensity and its applications
  • Learn about the decibel scale and its significance in acoustics
  • Explore the physics of sound waves and their properties
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Acoustics students, audiologists, sound engineers, and anyone interested in the principles of sound amplification and hearing aids.

whoknows123
A person wears a hearing aid, which makes a sounds louder by 50 dB. This a) means the sound intensity is increased by 100,000 times.
b) This also means that the amplitude of the soundwave is increased by ______ times?

I know Intensity is portportinal to (Amplitude)^2... so does that mean I squareroot the 100,000 times of the intensity to find part b?
 
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whoknows123 said:
A person wears a hearing aid, which makes a sounds louder by 50 dB. This a) means the sound intensity is increased by 100,000 times.
b) This also means that the amplitude of the soundwave is increased by ______ times?

I know Intensity is portportinal to (Amplitude)^2... so does that mean I squareroot the 100,000 times of the intensity to find part b?

Yes. Correct.
 
Yes.

- Warren
 

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