Intensity of the incident light

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Homework Statement



Unpolarized light is incident on a system of three polarizers. The second polarizer is oriented at an angle of 33.0° with respect to the first and the third is oriented at an angle of 45.0° with respect to the first. If the light that emerges from the system has an intensity of 2.3 W/m2, what is the intensity of the incident light?

Homework Equations



Iout=Iincos2[tex]\theta[/tex]

The Attempt at a Solution



I know that after I0 passes through the first polarizer, it is 1/2I0. After it passes through the second, I thought it would be 1/2I0cos2(33), and after it passes through the third, 1/2I0cos2(33)cos2(45).
This would all equal 2.3, which I was given.
So I set up my final equation as:
1/2I0cos2(33)cos2(45) = 2.3, or
I0= 2.3 / (1/2cos2(33)cos2(45).

I solved and got 13.08, but that is incorrect. Can anyone offer any insight? Thanks.
 

Answers and Replies

  • #2
Redbelly98
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For the third polarizer, use the angle between it and the second polarizer.

45° is the angle between the third and first polarizer.
 

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