Intensity of the incident light

  • Thread starter Thread starter vrobins1
  • Start date Start date
  • Tags Tags
    Intensity Light
Click For Summary
SUMMARY

The discussion centers on calculating the intensity of incident light on a system of three polarizers, where the second polarizer is oriented at 33.0° and the third at 45.0° relative to the first. The final intensity after the polarizers is given as 2.3 W/m². The user initially calculated the incident intensity using the formula Iout = Iinc * cos²(θ), but misapplied the angles between the polarizers. The correct approach requires using the angle between the second and third polarizers for the final calculation.

PREREQUISITES
  • Understanding of light polarization principles
  • Familiarity with the intensity formula Iout = Iinc * cos²(θ)
  • Knowledge of trigonometric functions and their applications
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Review the derivation of intensity through multiple polarizers
  • Study the effects of angle adjustments on light intensity
  • Learn about the implications of unpolarized versus polarized light
  • Explore practical applications of polarizers in optical devices
USEFUL FOR

Students studying optics, physics educators, and anyone interested in the practical applications of light polarization in technology.

vrobins1
Messages
21
Reaction score
0

Homework Statement



Unpolarized light is incident on a system of three polarizers. The second polarizer is oriented at an angle of 33.0° with respect to the first and the third is oriented at an angle of 45.0° with respect to the first. If the light that emerges from the system has an intensity of 2.3 W/m2, what is the intensity of the incident light?

Homework Equations



Iout=Iincos2[tex]\theta[/tex]

The Attempt at a Solution



I know that after I0 passes through the first polarizer, it is 1/2I0. After it passes through the second, I thought it would be 1/2I0cos2(33), and after it passes through the third, 1/2I0cos2(33)cos2(45).
This would all equal 2.3, which I was given.
So I set up my final equation as:
1/2I0cos2(33)cos2(45) = 2.3, or
I0= 2.3 / (1/2cos2(33)cos2(45).

I solved and got 13.08, but that is incorrect. Can anyone offer any insight? Thanks.
 
Physics news on Phys.org
For the third polarizer, use the angle between it and the second polarizer.

45° is the angle between the third and first polarizer.
 

Similar threads

Replies
4
Views
2K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K