Interaction between two material points

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Two material points with unit mass interact through a non-symmetric potential V, dependent on their coordinates x and y. To determine the forces acting on these points at time t=0, the negative gradient of the potential, F = -∇U(x,y), is used. Simplifying the problem to one dimension allows expressing y as a function of x, but both coordinates remain on the same straight line. The forces can be derived from the derivatives of the potential with respect to x and y, but the discussion notes that mechanical energy is not conserved over time. This indicates complexities in the system's evolution that may affect the forces experienced by the points.
kreeb
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Hi,
there are two material points with unitary mass that can move on a stright line. They are subject to a potential of mutual interaction V which depends on x and y and it's not symmetric, where x and y are the coordinates of the two points.
I can choose in the istant 0 v1,v2,x and y. How can I find, in t=0, the force that x and y suffer because of the potential?
 
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I may have misunderstood the question, but if you have the potential field at every point, the force felt should be:

F=-∇U(x,y).

F is the negative of the gradient of U

to simplify even further, if you say the masses move on straight lies only, this becomes a one dimensional problem, as you can express y as a function of x.
 
Yes, but x e y are coordinates along the same straight line.
I might get the two forces by the derivative of the potential respect to x and y with changed sign, but if you look at how the system evolves at regular intervals, the mechanical energy is not conserved.
 
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