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jorgerp24601
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- Homework Statement
- I'm working on my undergraduate thesis about nitrogen vacancies and a part of it consists in emulating the results obtained in Appendix A of the paper titled "Coupling a Surface Acoustic Wave to an Electron Spin in Diamond via a Dark State" (in case further detail is needed), and I'm currently stuck in the part where the transformation to the interaction picture occurs.
- Relevant Equations
- Basically what I need to calculate is the interaction picture of a hamiltonian of the form:
$$H=\hbar \omega_m \hat{b}^+\hat{b}-\hbar\nu|1><1|-\hbar\frac{g^2}{\omega_m}|e><e|+\hbar\frac{\Omega}{2}\left(e^{-i\omega t+\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}|e><1|+H.c. \right)$$
Where b is the bosonic anihilation operator.
What I have tried to do is to separate the exponential of the unitary transformation operator to the interaction picture into three different Hilbert "subspaces" like:
$$e^{i\frac{H_0}{\hbar}t}=e^{i\omega_m \hat{b}^+\hat{b}}\otimes e^{-i\hbar\nu|1><1|} \otimes e^{-i\frac{g}{\omega_m}|e><e|t}$$
Therefore, each one of the operators in the tensor product act only in their corresponden subspace. In that case, the result is:
$$H_I=\hbar\frac{\Omega}{2}e^{i\omega_m \hat{b}^+\hat{b}}\left(e^{i\left(\nu-\frac{g^2}{\omega_m}-\omega\right)}e^{\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}|e><2|+H.c\right) e^{-i\omega_m \hat{b}\hat{b}^+}$$
So, I think the next and final step I have to do is to evaluate:
$$e^{i\omega_m \hat{b}^+\hat{b}t}e^{\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}e^{-i\omega_m \hat{b}\hat{b}^+t}$$
And there is where I'm currently stuck. According to the paper and if my reasoning is right, that must be:
$$e^{i\omega_m \hat{b}^+\hat{b}t}e^{\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}e^{-i\omega_m \hat{b}\hat{b}^+t}=e^{-\frac{g}{\omega_m}\left(\hat{b}^+e^{i\omega_m t}-\hat{b}e^{-i\omega_m t}\right)}$$
However, I have tried expanding the exponentials in a Taylor series and that didn't seem to work or at least it got messy to the point I couldn't follow what I was doing. I don't know if I'm doing wrong or if the negative sign before g/wm in the final result is a mistake.
Thank you so much to whoever is reading this and thank you even more to whoever helps me!
$$e^{i\frac{H_0}{\hbar}t}=e^{i\omega_m \hat{b}^+\hat{b}}\otimes e^{-i\hbar\nu|1><1|} \otimes e^{-i\frac{g}{\omega_m}|e><e|t}$$
Therefore, each one of the operators in the tensor product act only in their corresponden subspace. In that case, the result is:
$$H_I=\hbar\frac{\Omega}{2}e^{i\omega_m \hat{b}^+\hat{b}}\left(e^{i\left(\nu-\frac{g^2}{\omega_m}-\omega\right)}e^{\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}|e><2|+H.c\right) e^{-i\omega_m \hat{b}\hat{b}^+}$$
So, I think the next and final step I have to do is to evaluate:
$$e^{i\omega_m \hat{b}^+\hat{b}t}e^{\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}e^{-i\omega_m \hat{b}\hat{b}^+t}$$
And there is where I'm currently stuck. According to the paper and if my reasoning is right, that must be:
$$e^{i\omega_m \hat{b}^+\hat{b}t}e^{\frac{g}{\omega_m}(\hat{b}^+-\hat{b})}e^{-i\omega_m \hat{b}\hat{b}^+t}=e^{-\frac{g}{\omega_m}\left(\hat{b}^+e^{i\omega_m t}-\hat{b}e^{-i\omega_m t}\right)}$$
However, I have tried expanding the exponentials in a Taylor series and that didn't seem to work or at least it got messy to the point I couldn't follow what I was doing. I don't know if I'm doing wrong or if the negative sign before g/wm in the final result is a mistake.
Thank you so much to whoever is reading this and thank you even more to whoever helps me!
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