Interactions of Light and Matter

[EskShift]

Homework Statement

The tungsten cathode in an electron microscope has a work function of 4.5 eV and is heated to release electrons that are initially at rest (near the cathode). The electrons are accelerated by a potential difference that creates a beam with a de Broglie wavelength of 0.040 nm.

Calculate the kinetic energy, in Joules, of an electron in the beam.

Homework Equations

Ek = hf - w

F = c / \lambda

The Attempt at a Solution

Ek = hf - w
F = c / \lambda
Therefore, Ek = h x (c/\lambda) - w
Ek = 6.63 x 10^-34 x (3 x 10^8/0.040 x 10^-9) - 4.5
Ek = -4.5?
Feel like I am doing something very wrong here...

 

[Doc Al]

How does the de Broglie wavelength relate to the particle's momentum?