Interference by amplitude division (double reflection) for wedges

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Homework Help Overview

The problem involves interference patterns created by light reflecting off a wedge-shaped layer of transparent wax on a glass plate. The wax has a varying thickness, and the discussion centers on determining the angle of the wedge and the positions of bright fringes based on the interference of light waves reflecting from the two surfaces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the thickness of the wax layer and the angle α, questioning how to calculate the angle and the positions of bright fringes. There is discussion about the phase changes that occur upon reflection from different media and how these affect the interference pattern.

Discussion Status

Some participants have provided insights into the phase changes upon reflection and the conditions for bright fringes. There is ongoing exploration of how to apply these concepts to find specific values for x where bright fringes occur, but no consensus has been reached on the exact approach to take.

Contextual Notes

The problem is constrained by the specific parameters of the wax and glass, including their refractive indices and the uniform tapering of the wax layer. Participants are working within the framework of these given values while discussing the implications for the interference pattern.

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Homework Statement



Transparent wax of refractive index n=1.3 is deposited on top of a glass plate of width 1cm and refractive index n=1.5. The thickness of the wax is 0.01mm at one end of the plate and tapers uniformly to zero at the other end of the plate, which is defined to be at x=0. At this end the surface of the wax and of the glass form a small angle α. Light is incident on the plate from above, i.e. it goes through the wax, and is normal to the surface of the glass plate. Fringes are formed due to interference of light reflected from the top surface of the wax and from the glass.

i) Find the value of α.
ii) At what values of x do bright fringes occur if λ=520nm?

Homework Equations



Thickness of wedge, d = x tan(α) ≈ αx

The Attempt at a Solution



i) tan(α)=0.01/10 = 1×10-3 radians

ii) I'm not sure whether bright fringes occur at xn = ((ρ+0.5)λ)/2nα) or xn = (ρλ/2nα)
 
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You see the wedge from above. The bright fringes occur at those places where the phase difference between the ray reflected from the wax and that reflected from the glass makes integer times 2pi. The phase can change upon reflection and during traveling through a medium. The phase change upon reflection is pi when the wave arrives from a lower index medium to the surface of a higher index material, and it is zero in the opposite case. What is the phase change when the wave reflects from the wax and what is it when it reflects from the glass?

ehild
 
ehild said:
You see the wedge from above. The bright fringes occur at those places where the phase difference between the ray reflected from the wax and that reflected from the glass makes integer times 2pi. The phase can change upon reflection and during traveling through a medium. The phase change upon reflection is pi when the wave arrives from a lower index medium to the surface of a higher index material, and it is zero in the opposite case. What is the phase change when the wave reflects from the wax and what is it when it reflects from the glass?

ehild

Does that mean the phase change when light reflects from wax = pi and the phase change when light reflects from glass = pi?
How would I use this to find the values of x for which bright fringes occur?
 
Last edited:
As the phase changes at the interfaces cancel, the total phase difference is the phase shift inside the layer. It is
(4pi/λ) nd =2kπ,
where k is integer and d is the thickness of the layer. That means that bright fringes occur where the thickness is d=kλ /2n.

ehild
 
Thank you so much!
 
You are welcome.ehild
 

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