Interference with two speakers

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To determine the closest distance to speaker B for destructive interference, the wavelength of the sound waves needs to be calculated first. Given the frequency of 172 Hz and the speed of sound at 344 m/s, the wavelength is found to be 2 meters. Destructive interference occurs at half wavelengths, meaning the closest point to speaker B for this effect is 1 meter away. The discussion highlights the importance of understanding wave properties in sound interference. Overall, the problem effectively illustrates the concept of destructive interference in acoustics.
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Homework Statement


Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 Hz. You are 8.00m from speaker A. Take the speed of sound in air to be 344m/s .

What is the closest you can be to speaker B and be at a point of destructive interference?
Express your answer in meters


I really don't have a clue on how to solve this problem.
 
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destructive interference occurs at half wavelengths. Therefore with the quantities given, solve for wavelength which = 2m. Therefore the closest you can be to speaker B is 1 m and possibly experience destructive.

What a joke.
 
Uh, good job! It was actually a pretty good question. You nailed it.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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