Interference with two speakers?

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To determine the distance a listener must walk from the central maximum to the first minimum in loudness when two speakers emit sound in phase, one must consider the interference pattern created by the speakers. The listener is positioned 8m from the midpoint of the speakers, which are 1m apart, and the sound frequency is 1000Hz with a speed of sound at 340m/s. The first minimum occurs when the path difference between the sounds from the two speakers is half a wavelength. Calculating the wavelength as 0.34m, the listener needs to walk approximately 0.17m from the central maximum to reach the first minimum in loudness. Understanding the phase relationship at this point reveals that the sound waves are out of phase, leading to destructive interference.
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Interference with two speakers??!

Two speakers placed 1m apart emit sound of frequency f=1000Hz in phase. A listener walks along a line that is parallel to the line joining the two speakers and 8m from their midpoint. What is the distance he has to walk from the central maximum in loudness to the first minimum in loudness? use 340m/s for the speed of sound

I have done similar questions to this with no problem, but this question has completely stumped me and I don't know where to start.

Thanks
 
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what can you say about the phase of the sounds received at the point where there is a minimum? what does this mean for the distances to the speakers?
 

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