Internal Energy Dependence for a Fixed System in Fixed Phase

AI Thread Summary
In a closed system without phase transitions, internal energy does not depend solely on temperature; it also relies on pressure, especially for real gases and other materials. The internal energy comprises microscopic kinetic and potential energy, with the kinetic energy primarily influenced by temperature. Pressure affects potential energy, which is significant in non-ideal gases where increased pressure leads to decreased volume and increased potential energy. For liquids and solids, internal energy also depends on pressure, but changes are minimal unless pressure variations are substantial. The relationship between internal energy, temperature, and pressure can be explored further in thermodynamics literature.
0pt618
Messages
25
Reaction score
1
For a given closed system that does not experience phase transitions, does its internal energy depend only on its temperature?
 
Physics news on Phys.org
0pt618 said:
For a given closed system that does not experience phase transitions, does its internal energy depend only on its temperature?
No. This is true only for an ideal gas. For real gases beyond the ideal gas region (i.e., higher pressures) and for other materials, the internal energy also depends on pressure.

Chet
 
  • Like
Likes 0pt618
Chestermiller said:
No. This is true only for an ideal gas. For real gases beyond the ideal gas region (i.e., higher pressures) and for other materials, the internal energy also depends on pressure.

Chet

Hi Chet - thanks. I have some follow up questions, and let's exclude ideal gases from the following discussion - let's consider only liquids, solids, and non-ideal gases.

From what I understand, the internal energy consists of two parts: microscopic kinetic energy and microscopic potential energy. Since the kinetic energy portion (to a good approximation at least) depends solely on temperature, then it must mean the pressure dependence comes about through potential energy - in other words, pressure affects and only affects potential energy. Am I correct?

I can envision how this is true for an non-ideal gas: As the pressure is increased, the volume decreases and the potential energy increases. (And the temperature can be kept constant during this process.)

But does the internal energy of a liquid or solid material (that does not change phase) depend on pressure? I would think that a liquid or solid does not change much as pressure is varied, as long as the pressure variation is not "too great". Am I right? Can we do something to a liquid or solid that changes only its microscopic potential energy (while maintaining the same temperature)?

Thanks,
David
 
0pt618 said:
Hi Chet - thanks. I have some follow up questions, and let's exclude ideal gases from the following discussion - let's consider only liquids, solids, and non-ideal gases.

From what I understand, the internal energy consists of two parts: microscopic kinetic energy and microscopic potential energy. Since the kinetic energy portion (to a good approximation at least) depends solely on temperature, then it must mean the pressure dependence comes about through potential energy - in other words, pressure affects and only affects potential energy. Am I correct?
Yes.
I can envision how this is true for an non-ideal gas: As the pressure is increased, the volume decreases and the potential energy increases. (And the temperature can be kept constant during this process.)

But does the internal energy of a liquid or solid material (that does not change phase) depend on pressure? I would think that a liquid or solid does not change much as pressure is varied, as long as the pressure variation is not "too great". Am I right?
Yes. Exactly right.
Can we do something to a liquid or solid that changes only its microscopic potential energy (while maintaining the same temperature)?
I am not an expert on how this all plays out microscopicly. I'm a continuum guy. But, you can look in Thermo books. They give an equation for dU in terms of dT and dP. The coefficient of dP follows exclusively from equation of state P-V-T behavior of the material.

Chet
 
  • Like
Likes 0pt618
Thanks, Chet.
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...
Back
Top