Interpret this geometrically, as a statement about parallelograms.

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Homework Help Overview

The discussion revolves around a mathematical statement involving vectors in ℝk, specifically the relationship between the sums of squares of certain vector expressions and their geometric interpretation in the context of parallelograms.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the geometric interpretation of the equation, particularly how it relates to the properties of parallelograms. Some express confusion about the parallelogram aspect, while others attempt to clarify the relationship between the sides and diagonals.

Discussion Status

There is an ongoing exploration of the geometric interpretation, with some participants providing insights into the properties of parallelograms. A few have indicated a clearer understanding after revisiting their sketches, but the discussion remains open without a definitive consensus.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of exploration and the information available for discussion.

Jamin2112
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Homework Statement



Prove that

|x+y|2 + |x-y|2 = 2|x|2 + 2|y|2

if x and y are elements of ℝk

Homework Equations



Ordinary stuff

The Attempt at a Solution




Got the first part, but I don't understand the parallelogram thing yet. The little sketch I drew didn't help.

screen-capture-1-34.png
 
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In a parallelogram the sum of squares of sides equals the sum of squares of its diagonals
 
Jamin2112 said:
Prove that

|x+y|2 + |x-y|2 = 2|x|2 + 2|y|2

if x and y are elements of ℝk
since [itex]\left|X+Y\right|[/itex] and [itex]\left|X-Y\right|[/itex] are diagonals of the parallelogram with [itex]\left|X\right|[/itex]and [itex]\left|Y\right|[/itex] as the sides , it states the property
"In a parallelogram The sum of squares of diagonals equals the sum of squares of the sides"
 
Last edited:
vrmuth said:
since [itex]\left|X+Y\right|[/itex] and [itex]\left|X-Y\right|[/itex] are diagonals of the parallelogram with [itex]\left|X\right|[/itex]and [itex]\left|Y\right|[/itex] as the sides , it states the property
"In a parallelogram The sum of squares of diagonals equals the sum of squares of the sides"

Drew the picture again. Now I understand it. Indeed: On a parallelogram, the sum of squares of diagonals equals the sum of squares of the sides
 

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