- #1

aisha

- 584

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The question was determine the coordinate of the intersection point of

[tex] \frac {(x-3)^2} {9} + \frac {y+2)^2} {4} =1 [/tex] and [tex] y=2x-3 [/tex]

I after putting the second equation into the first and then expanding and solving for x and y I got my two intersection points to be

(1.33,-0.34) and (0.169,-2.66) These values work well when plugged into the equation both coordinates equal 36 from the first equation when denominators are eliminated.

I wanted to check this with the graphing calculator but was having a hard time putting the first equation into y= form. Can someone help me out a little please