Intersections of a Line and a Parabola: Solving for t

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Homework Statement


Consider the line L(t)=<1+5t, 3+t>. Then L intersects:
1. The x-axis at the point (-14,0) when t= -3
2. the y-axis at the point (0, 14/5) when t=(-1/5)
3. the parabola y=x^2 at the points ____ and ____ when t=____ and ____.


Homework Equations



y=x^2?

The Attempt at a Solution



I really have no idea what this is asking. I tried setting y = x^2 so (3+t) = (1+5t)^2 with the results of (110/50) and (272/50) but it didn't work. I really have no idea what it's asking. I'm sure it's a very simple problem because this is number 2/16 on my homework and I've already gotten all the others correct (including #1 and #2 of this problem), I just need a little push in the right direction.
Thanks!
 
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I think you are doing the right thing. But you are getting the wrong solutions for t. Unfortunately, when I work it out I get a pretty messy solution for the two values of t. Can you show how you solved it?
 
NEVER MINE I figured it out... basic algebra problem it works now!
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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