Introductory Simple Harmonic Motion Problem

AI Thread Summary
To find the maximum speed of the tympanic membrane's oscillation given a sound wave with a frequency of 600 Hz and an amplitude of 1.0 nm, the formula Vmax = ωA is used, where ω is the angular velocity. The angular velocity is calculated as ω = 2πf, leading to ω = 2π x 600 Hz. Substituting this value back into the equation provides the maximum speed. It is recommended to perform the algebra before inserting numerical values for clarity. Overall, the approach to solving the problem is straightforward and emphasizes the importance of understanding the underlying equations.
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Q: When a sound wave with a certain intensity is detected by the tympanic membrane, the amplitude of the resultant motion is 1.0 nm (1.0 x 10-9 m). If the frequency of the sound is 600 Hz, what is the maximum speed of the membrane oscillation?

My answer:

1)Vmax = wA (where w= angular velocity)
2)w = 2(pi) x f = 2(pi) x 600 Hz
3) ^Then I insert the above result of 'w' into the first equation

Is this correct? Additionally, is there a simpler way to do this?

Any replies will be very much appreciated :)
 
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That's pretty much it yep - multiplying a bunch of numbers together is as simple as it gets.

It is best practice to do the algebra before you plug in the numbers though ... so for oscillations of amplitude A and frequency f, the max speed for the membrane is ##v = \omega A = 2\pi f A##.
 
That seems simple enough, I'd think.
 
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