- #1
kent davidge
- 933
- 56
The Lagragian ##\mathcal L_e = e(\lambda)^{-1} \mathcal L - \frac{1}{2}m^2 e(\lambda)##, with ##\mathcal L## not depending on ##\lambda##, transform as ##\delta L_e = \frac{d}{d\lambda} (\epsilon (\lambda) \mathcal L_e)##* under the reparametrization ##\lambda \rightarrow \lambda + \epsilon(\lambda)##, according to a paper that I'm reading.
Above I reproduced the expressions exactly how they are given in the paper. However, I think there's a mistake in *. Shouldn't the right-hand-side be ##\delta (\epsilon (\lambda) \mathcal L_e)## instead?
Also, I was able to derive * myself only for the second term in ##\mathcal L_e##. Does anyone know how to derive for the first term?
Above I reproduced the expressions exactly how they are given in the paper. However, I think there's a mistake in *. Shouldn't the right-hand-side be ##\delta (\epsilon (\lambda) \mathcal L_e)## instead?
Also, I was able to derive * myself only for the second term in ##\mathcal L_e##. Does anyone know how to derive for the first term?