I need to figure out what or if what I found is why it is.(adsbygoogle = window.adsbygoogle || []).push({});

I need the inverse of a polar equation graphed.

When I say inverse I mean switching the variables and then placing it in proper form again.

I have the equation r=Cos(θ) which produces the following graph.

http://images.iceogen.net/cospheta.gif [Broken]

What I need is r=ArcCos(θ), when put in Mathematica it gives me this.

http://images.iceogen.net/inverse.gif [Broken]

Between the left end of the line and the x and y axises multiple values of pheta exist but they are not ploted, I believe it is because they aren't real, but why? and can this be properly graphed?

Mathematicas gives me these errors:

{ArcCos[θ] Cos[θ],ArcCos[θ] Sin[θ]} does not evaluate to a pair of real numbers at θ = 1.0453537892798384

{ArcCos[θ] Cos[θ],ArcCos[θ] Sin[θ]} does not evaluate to a pair of real numbers at θ = 1.011390375748485

{ArcCos[θ] Cos[θ],ArcCos[θ] Sin[θ]} does not evaluate to a pair of real numbers at θ = 1.0036610320397505

Any answers would be much appriciated

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# Homework Help: Inverse Polar Graph

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