- #1
center o bass
- 560
- 2
Hello! I'm reading up on Hamiltonian mechanics and i stumbled on the fact that the curl of the vector potential can be expressed as
[tex]B_k = \sum_k \epsilon_{kij}\frac{\partial A_i}{\partial x_j}[/tex]
Now the text that I'm reading says that this formula can be inverted as
[tex] \sum_k \epsilon_{kij} B_k = \frac{\partial A_j}{\partial x_i} - \frac{\partial A_i}{\partial x_j}[/tex]
But I then wondered how this inversion would be accomplished?
I suspect the formula [tex]\sum_k \epsilon_{kij} \epsilon_{klm}= \delta_{il}\delta_{jm} - \delta_{im}\delta_{jl}[/tex] to be involved.
[tex]B_k = \sum_k \epsilon_{kij}\frac{\partial A_i}{\partial x_j}[/tex]
Now the text that I'm reading says that this formula can be inverted as
[tex] \sum_k \epsilon_{kij} B_k = \frac{\partial A_j}{\partial x_i} - \frac{\partial A_i}{\partial x_j}[/tex]
But I then wondered how this inversion would be accomplished?
I suspect the formula [tex]\sum_k \epsilon_{kij} \epsilon_{klm}= \delta_{il}\delta_{jm} - \delta_{im}\delta_{jl}[/tex] to be involved.