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Inverting Amplifier

  • Thread starter naspek
  • Start date
  • #1
181
0
Hey there.. this is my lab discussion.. which i'll attend it this coming monday..
however.. there are questions that i'm not sure the formula to calculate it..
i really hope u guys can varified or corrected my formula.. =)


Homework Statement


Vin(pp) = 1.0V

is it Vin = Vin(pp) / 2 ?

Vout(pp) = -(Rf / R1) Vin(pp)

What are the peak voltages across R1 and Rf?

Calculate the peak currents of R1 and Rf

Homework Equations



Current through R1 = Vin(pp)/R1

Current through Rf = Vout(pp)/Rf

to find peak voltage, can i use voltage divider rule?

VR1 = 10k/43k x Vin
VRf = 33k/43k x Vin


:smile:
 

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Answers and Replies

  • #2
CEL
656
0
pp means peak-to-peak
 
  • #3
181
0
so.. my Vin = Vin(pp) / 2?
 
  • #4
CEL
656
0
so.. my Vin = Vin(pp) / 2?
If Vin is the peak voltage, yes.
 

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