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Inverting Amplifier

  1. Feb 25, 2010 #1
    Hey there.. this is my lab discussion.. which i'll attend it this coming monday..
    however.. there are questions that i'm not sure the formula to calculate it..
    i really hope u guys can varified or corrected my formula.. =)


    1. The problem statement, all variables and given/known data
    Vin(pp) = 1.0V

    is it Vin = Vin(pp) / 2 ?

    Vout(pp) = -(Rf / R1) Vin(pp)

    What are the peak voltages across R1 and Rf?

    Calculate the peak currents of R1 and Rf

    2. Relevant equations

    Current through R1 = Vin(pp)/R1

    Current through Rf = Vout(pp)/Rf

    to find peak voltage, can i use voltage divider rule?

    VR1 = 10k/43k x Vin
    VRf = 33k/43k x Vin


    :smile:
     

    Attached Files:

  2. jcsd
  3. Feb 26, 2010 #2

    CEL

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    pp means peak-to-peak
     
  4. Feb 26, 2010 #3
    so.. my Vin = Vin(pp) / 2?
     
  5. Feb 26, 2010 #4

    CEL

    User Avatar

    If Vin is the peak voltage, yes.
     
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