Invisibility Cloaks: Understand How They Work

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Invisibility cloaks utilize advanced materials to manipulate light, allowing objects to become less visible or seemingly disappear. These cloaks often rely on metamaterials, which can bend light around an object, creating the illusion of invisibility. The discussion emphasizes the importance of understanding the basic principles of optics and light manipulation without delving into overly complex scientific jargon. Simplified explanations can help in grasping how these technologies function, making them accessible for educational purposes. Overall, invisibility cloaks represent a fascinating intersection of physics and engineering.
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Invisibilty cloaks ?

Hey i have a school homework which is : to do a presentation about

HOW do Invisibility Cloaks work ??

OFC i searched on the net but all what i found is VERY VERY complicated explanations !
so please i want a detailed explintations and at the same time not to be very complicated ( SIMPLE)


thank you
 
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Welcome.

We cannot do your homework for you, but we can assist you. Put forth some of your ideas and we'll discuss them.
 
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bassim22 said:
Hey i have a school homework which is : to do a presentation about

HOW do Invisibility Cloaks work ??

OFC i searched on the net but all what i found is VERY VERY complicated explanations !
so please i want a detailed explintations and at the same time not to be very complicated ( SIMPLE)


thank you

Here's a recent thread from one of our sub-forums where the concept was discussed:

https://www.physicsforums.com/showthread.php?t=469555

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Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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