Ionization Energy: Homework Problem Solving

[Magnetic Boy]

Homework Statement

.[/B]
Suppose the energy difference between the states n=2 and n=3 is E(eV), in an hydrogen atom. then the ionization potential in volts is: A) 13.2E B) 7.2E C) 3.2 E D) 0.56E

Homework Equations

E_n = -13.7 × Z^2÷n^2

The Attempt at a Solution

I just know the ionization energy is equal to the total energy in last stationary state. but i can't apply the concept on this problem.

 

[malawi_glenn]

E = (-13.7)/9-(-13.7)/4 is the energy difference

And the ionization energy is 13.7eV

what do you think you have to do now?

 

[Joyal Babu]

You got the energy in each state.Divide that by 1.60218e-19 you get the ionization potential of each state in eV.Now find the difference between n=2 and n=3 states.Give that as E.Find ionization potential in n=1.See what multiple of E is that.You got the answer.They gave "ionization potential in volts" to confuse you.
Volt*Q(e)=eV.In this problem both have the same numerical value.

 

[Magnetic Boy]

You got the energy in each state.Divide that by 1.60218e-19 you get the ionization potential of each state in eV.Now find the difference between n=2 and n=3 states.Give that as E.Find ionization potential in n=1.See what multiple of E is that.You got the answer.They gave "ionization potential in volts" to confuse you.
Volt*Q(e)=eV.In this problem both have the same numerical value.

Thank you. It was helpful. And solved.