Is Conservation of Momentum Essential for Understanding Particle Interactions?

  • Thread starter Thread starter matpo39
  • Start date Start date
  • Tags Tags
    Momentum
AI Thread Summary
Conservation of momentum is critical for understanding particle interactions, particularly in scenarios involving photons and electrons. When a photon with momentum p_γ is deflected by a free electron, the momentum components must be analyzed in both the x and y directions. The momentum of the electron after the interaction can be expressed as p_e = p_γ' in the -y direction, with the x component calculated using p_ex = √(p_γ² - p_γ'² - p_ey²). This approach emphasizes that the total momentum before the interaction equals the total momentum after the interaction. Understanding these principles is essential for accurately analyzing particle interactions.
matpo39
Messages
40
Reaction score
0
if you have a photon with momentum p_\gamma traveling in the +x direction which is then deflected off a free electron and now the photon has momentum p_\gamma' and isin the +y direction.
so the components of momentum for the electron would be
p_e = p_\gamma' in the -y direction and for the x component

p_ex= \sqrt{p_\gamma^2-p_\gamma'^2-p_ey^2}

does this seem like the correct approach to this problem?
 
Physics news on Phys.org
What was the question?
Could this be the answer? That is the components of the momentum of the system before the interaction should be equal to the components of the momentum of the system after the interaction.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top