Is energy profile of a spring asymmetric with +x and -x?

AI Thread Summary
The discussion centers on the energy profile of a spring and its symmetry in relation to elastic potential energy (EPE). The key equation used is E = 1/2 kx^2, which indicates that EPE is dependent on the square of the displacement (x). The participant notes that EPE should be maximum at 0, 0.4, and 0.8, but the mark scheme only accepts 0 and 0.8 as valid points. The confusion arises regarding the energy profile's symmetry and the status of EPE when the mass is at rest. Ultimately, the participant acknowledges a missed detail regarding the energy state of the spring when the mass is stationary.
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Homework Statement


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The problem is with part b(ii). This is an A level question so only elementary concepts are to be used.

Homework Equations


$$E = \frac{1}{2}kx^2 $$

The Attempt at a Solution



EPE should be max at 0, 0.4, 0.8 since E is a function of $x^2$. However, mark scheme only accepts 0 and 0.8 only. It is my understanding that energy profile of a spring is symmetric under compression and expansion, but if so, why is 0.4 not acceptable?
 

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When the mass is hanging at rest as in part (a), does the spring have any elastic potential energy?
 
Ah, right, I missed that. Thanks!
 
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