Is f(x) = cos^2(x) + sin^2(x) a periodic function?

  • Thread starter Thread starter jkface
  • Start date Start date
  • Tags Tags
    Function Periodic
jkface
Messages
16
Reaction score
0

Homework Statement


Is f(x) = cos^2(x) + sin^2(x) a periodic function?


Homework Equations


sin^2(x) + cos^2(x) = 1


The Attempt at a Solution


This question is just something that randomly came to my mind (not a homework problem). I know cos^2(x) and sin^2(x) are both periodic functions, but is sin^2(x) + cos^2(x) a periodic function too? If so, what would be its fundamental frequency?
 
Physics news on Phys.org
No, sin^2(x) + cos^2(x) = 1 which we know is not periodic, but constant.
 
Zondrina said:
No, sin^2(x) + cos^2(x) = 1 which we know is not periodic, but constant.

Indeed, as Zondrina mentioned, it is not periodic. Typically, we say a function f(x) is periodic if there is a smallest positive integer P≠0 for which f(x+P)=f(x). The number P is then the period. Since sin^2(x)+cos^2(x)=1:=1(x), it is not periodic, because 1(x+P)=1=1(x) for any P (so in particular, there isn't a smallest one).
 
Last edited:
Technically a constant function is periodic but has no fundamental period, but it is kind of silly to refer to it in such a way.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top