Is My Calculation of Electric Field Correct Using the Paint Document?

AI Thread Summary
The calculation of the electric field is based on the equations v = kq/r and E = kq/r^2. The user is confused about their result of 2500 for E, noting that the potential changes non-linearly between circles. It is emphasized that the electric field is derived from the negative potential gradient, -ΔV/Δd. To accurately determine E, both circles above and below the point of interest should be considered. Clarifying these concepts will help correct the calculation.
Miike012
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The question is in the paint doc...

What I did...

1st eq.
v = kq/r

q = vr/k

2nd equ.

E = kq/r^2

where am I going wrong...? For E I am getting 2500
 

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The potential is not linear function of the distance, it changes 25 V from the second circle to the third one, and 50 V from the third circle to the fourth. The electric field is negative potential gradient, -ΔV/Δd. Use both circles, below and above the point shown to get it.

ehild
 

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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