Is My Calculation of Force and Acceleration Correct?

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The discussion revolves around calculating force and acceleration using the equation F = ma. The initial calculation of force as 13.78 N leads to an acceleration of 2.3 m/s². Participants emphasize the need to integrate acceleration to find velocity, clarifying that force must first be converted to acceleration. After correcting the approach, the final velocity calculation yields 11.63 m/s. The conversation also highlights the importance of presenting work as text for clarity and accessibility.
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How do I even start that? I replace t with 7.6

so F(7.6) = 13.78 which is the force, correct?

F= ma

13.78 = 6 kg x a

a = 2.3 m/s2

is this correct so far? am i on the right route?
 
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You need to use the Homework Template.

Have you learned the integral calculus?
 
PeroK said:
You need to use the Homework Template.

Have you learned the integral calculus?
very briefly. is it required to do this problem?

isn't integral calculus just +1 to the exponent and divide the whole term by the new exponent??

hint says the integral of acceleration is velocity but the only equation they give us is for force.
 
The force is not constant, it is continually changing with time.

Using calculus, what is the general expression for velocity in terms of acceleration?
 
NascentOxygen said:
The force is not constant, it is continually changing with time.

Using calculus, what is the general expression for velocity in terms of acceleration?
integral i believe? since derivative of velocity gives you acceleration.
 
If you click on the capital sigma ##(\Sigma)## in the toolbar of the text entry box below you will see some useful symbols appear; among them is an integral sign.
 
goonking said:
integral i believe?
NascentOxygen said:
If you click on the capital sigma ##(\Sigma)## in the toolbar of the text entry box below you will see some useful symbols appear; among them is an integral sign.
so do I find the integral of F(t) to give me velocity?
 
goonking said:
so do I find the integral of F(t) to give me velocity?
That's close, but you have to be exact if you hope to get the right answer.

I hoped that by my pointing out the integral sign, you might be encouraged to use it. :wink:
 
NascentOxygen said:
That's close, but you have to be exact if you hope to get the right answer.

I hoped that by my pointing out the integral sign, you might be encouraged to use it. :wink:

F(t) is the only equation there I can integrate, how can I get a more exact answer?
 
  • #10
You know that the time integral of force doesn't have units of metres/second. So how can you convert your force into something that can be integrated to give velocity?
 
  • #11
NascentOxygen said:
You know that the time integral of force doesn't have units of metres/second. So how can you convert your force into something that can be integrated to give velocity?
convert force to acceleration? F = ma?
 
  • #12
goonking said:
convert force to acceleration? F = ma?
Right. And you can see that the "conversion" involves a proportionality constant.
 
  • #13
NascentOxygen said:
Right. And you can see that the "conversion" involves a proportionality constant.
I'm getting the answer to be 17.45 meters/sec.

is that what you are getting too?
 
  • #14
goonking said:
I'm getting the answer to be 17.45 meters/sec.

is that what you are getting too?

How did you get that answer?
 
  • #15
  • #16
It's wrong because you didn't integrate.

First step is to convert F(t) to a(t), acceleration as a function of time. Then integrate this a(t) to arrive at v(t).
 
  • #17
NascentOxygen said:
It's wrong because you didn't integrate.

First step is to convert F(t) to a(t), acceleration as a function of time. Then integrate this a(t) to arrive at v(t).
so to convert F(t) to a(t), do you just divide F(t) by the mass 6kg? since F=ma
 
  • #18
goonking said:
so to convert F(t) to a(t), do you just divide F(t) by the mass 6kg? since F=ma
Yes, that's it!
 
  • #19
NascentOxygen said:
Yes, that's it!
yes! the answer is 11.63 m/s.
thank you! finally I can move on
 
  • #20
We would appreciate it if you'd type in your working as text, rather than attach a pic. That way we can quote a line that needs attention, as well as it being more legible (usually), and for those using mobile devices the download is faster and far less costly. Please bear that in mind for future postings.
 
  • #21
NascentOxygen said:
We would appreciate it if you'd type in your working as text, rather than attach a pic. That way we can quote a line that needs attention, as well as it being more legible (usually), and for those using mobile devices the download is faster and far less costly. Please bear that in mind for future postings.
I'm not too familiar with posting my work as text. Do I need a program to do that?
 
  • #22
goonking said:
I'm not too familiar with posting my work as text. Do I need a program to do that?
That means you type it on your keyboard as F=ma and v(t)=∫a(t).dt :smile:

For more complicated mathematical expressions, you can start to learn Latex.
 
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