Is my graph of Ep/J against t/s for an oscillating object correct?

AI Thread Summary
The discussion revolves around verifying a graph of potential energy (E_p) against time (t) for an oscillating object. The user derived that E_p can be expressed as E_p = B sin(wt), indicating a sinusoidal pattern. While the shape of the curve is confirmed to be correct, there are concerns regarding the amplitude and y-axis values, suggesting that the graph should reflect potential energy variations above and below the x-axis. Ultimately, the user expresses satisfaction with the feedback received, indicating their understanding of the graph's characteristics. The conversation highlights the importance of both the shape and the scale in graphing oscillatory motion.
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Homework Statement


Picture004.jpg

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Hi,the question is draw a graph of E_{p} against t/s of the oscillating motion above,I've done it and have no exact answer in my hand,hoping some ppl to double check my answer that's all.My answer is here below

Homework Equations


E_{p}=mgh , where E_{p} is potential energy,m=mass,g=gravitational pull,h=height


The Attempt at a Solution


q.jpg

Correct?!
 
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You see, Ep=mgx, where x is the height of the end of the strip. Now, since the motion is simple harmonic (from the graph), x=A sin(wt) (equation of shm), therefore, Ep=mgA sin(wt), which can be rewritten as Ep=B sin(wt), where B is a constant (mgA). From this it seems that your solution is incorrect... The graph will look like fig 4.3, but the amplitude will be different...
 
Well I've drawn my amplitude all above x-axis as the E_{p} starts from 0-origin,then increases to max then back to zero again,forming a sinusoidal wave type pattern.The graph requested didn't put a requirement to be exact in amplitude.How different u mean?
 
Different as in, taking the potential when the rod is at the mean position to be zero, the graph should be above and below the curve.
 
your answer is correct but what people are saying that u are missing the values on the y axis, they are not the same values as on the first graph,
but the shape of the curve is correct,

because the starting point is 0, no it does not go above and below the x axis
 
Hey thanks a bunch!Solved!**
 
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