A mass M hangs in equilibrium on a spring. M is made to oscillate about the equilibrium position by pulling it down 10 cm and releasing it. The time for M to travel back to the equilibrium position for the first time is 0.5s. Which line, A to D, is correct for these oscillations?
A) Amplitude(cm) 10 , Period(s) 1.0
B) Amplitude(cm) 10 , Period(s) 2.0
C) Amplitude(cm) 20, Period(s) 2.0
D) Amplitude(cm) 20, Period(s) 1.0
I attempted to solve this without the use of equations, but I guess these could be relevant:
T = t/n
T = 1/f
a = -w*2 x
The Attempt at a Solution
I may have solved the problem without actually knowing it, but its good to make sure. My first guess is when I read "by pulling it down 10 cm and releasing it". I guessed this to be the amplitude since it was released from the extreme position (or atleast I think so), so that leaves me with anwser A or B. Since M was released from the extreme position, It means it would take it 2x0.5 seconds to get back and give us the time period.Therefore, I went for answer A.
Some confirmation would be great. Forgive me if I may have made some mistakes posting this or related - this is my first post on this site :)