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Is my proof of this sequence's divergence good enough?

  1. May 3, 2012 #1
    Ʃ n=1 to infinity of cos(n∏)
    letting an=cos(n∏), I rewrote this as (-1)^n=an.

    Using the nth term test i let the limit as n->∞ go to infinity. This value bounces back and forth between positive and negative, but I know clearly the value =/= 0, therefore it diverges by the nth term test.

    Is there anything I should add to my proof?
     
  2. jcsd
  3. May 3, 2012 #2


    Looks fine to me, although with a somewhat folkloric language as "bouncing back and forth" and "n-th term test", which I don't what

    is. Perhaps you meant simply that the series doesn't converge as its general element's sequence doesn't converge to zero, which is a necessary condition.

    DonAntonio
     
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