Is my statics approach correct for pushing a 1000lb cart up an inclined slope?

  • Context: Undergrad 
  • Thread starter Thread starter KramerKotz
  • Start date Start date
  • Tags Tags
    Cart Inclined Slope
Click For Summary
SUMMARY

The discussion centers on calculating the required force to push a 1000-pound cart up a 10-degree incline using proper statics principles. The user initially applies the coefficient of friction (Cf) to determine the force required, but later realizes that the rolling resistance coefficient is more appropriate for this scenario. The correct formula for the required force (Fr) includes the force parallel to the slope (Fw*Sin(10)) and the rolling resistance, rather than the friction force acting down the slope. This adjustment leads to more accurate calculations for motor power requirements.

PREREQUISITES
  • Understanding of basic physics concepts such as force, weight, and incline angles.
  • Familiarity with the coefficient of friction and rolling resistance principles.
  • Knowledge of statics and dynamics in mechanical systems.
  • Basic calculations involving trigonometric functions (sine and cosine).
NEXT STEPS
  • Research the differences between the coefficient of friction and rolling resistance coefficients.
  • Learn how to calculate rolling resistance for different wheel types and surfaces.
  • Explore motor power calculations based on force and velocity for inclined planes.
  • Investigate the effects of surface materials on friction and rolling resistance in mechanical applications.
USEFUL FOR

Mechanical engineers, robotics enthusiasts, and hobbyists involved in projects requiring the movement of heavy loads on inclines, particularly those interested in optimizing motor selection and performance calculations.

KramerKotz
Messages
2
Reaction score
0
Hey guys,

I am trying to figure out which motor to order for a side project of mine. I am trying to push a 1000 pound cart up a 10 degree incline. The cart has four elastomer wheels, and may possible encounter carpeted surfaces. I'm not quite sure what to expect in regards to a coefficient of friction yet on a carpeted surface, but I wanted to check my math a bit to understand if I am approaching this problem correctly:

Coefficient of Friction = Cf
Required Force = Fr
Weight = Fw
Force Normal to Slope = Fn = = Cf*Fw*Cos(10)
Force Parallel to Slope = Fw*Sin(10)

So Fr = [Cf*Fw*cos10] + [Fw*Sin(10)]?

Thanks for any help in advance!

I just wanted to double check if I am doing my statics correctly.
 
Physics news on Phys.org
The motor power depends on how fast you want to go up the slope eg power = force * velocity. The static force gives you the minimium torque required.

This equation..

Force Parallel to Slope = Fw*Sin(10)

is correct but I'm not so sure about the friction term. I think what you have used..

Cf*Fw*Cos(10)

.. is the friction between wheels and ground. For the driving wheels that force is actually acting up the slope not down it. I think you also need to find the rolling resistance instead. I'm not sure if that's typically the same.

Edit: I checked and they are very different. If the wheel doesn't slip no power is dissipated overcoming friction between tyre and ground. You need to use the rolling coefficient instead.
 
Last edited:
Thanks for the response. The coefficient of friction method seemed like it was returning really high values.

Is the COF based on a surface to surface contact and the rolling resistance is based on a point to surface contact?

It seems like that would results in some more reasonable values.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 11 ·
Replies
11
Views
8K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
18
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 6 ·
Replies
6
Views
4K