Is My Triple Integral Calculation Correct or Is There an Error in the Book?

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SUMMARY

The triple integral calculation of \(\int \int \int_{A} xyz \, dxdydz\) over the region \(A = \{(x,y,z); x^2+y^2+z^2 \leq 2, x \geq 0, y \geq 0, z \geq 0\}\) yields a result of \(\frac{8}{48}\), which is confirmed by multiple participants in the discussion. The book's assertion of \(\frac{1}{48}\) is incorrect. The integration was performed using spherical coordinates with the transformations \(x = \rho \sin\phi \cos\theta\), \(y = \rho \sin\phi \sin\theta\), and \(z = \rho \cos\phi\) within the specified limits.

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mikan
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Hi,
my result of

[tex]\int \int \int_{A} xyz dxdydz[/tex]

where

[tex]A = \{(x,y,z); x^2+y^2+z^2 \leq 2, x \geq 0, y \geq 0, z \geq 0 \}[/tex]

is

[tex]\frac {8}{48}[/tex],

but book says

[tex]\frac{1}{48}[/tex].

Is the book right? Could you please verify?

Thank you
Michael
 
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Hey Michael,

I also got 8/48 using:

[tex]x = \rho \sin\phi \cos\theta, y = \rho \sin\phi \sin\theta, z = \rho \cos\phi[/tex] with [tex]0 < \phi < \frac{\pi}{2}, 0 < \theta < \frac{\pi}{2}, 0 < \rho < \sqrt{2}[/tex]

so it looks to be correct, although I'd suggest checking everything one more time just to be sure.
 
Last edited:

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