Is Temperature the Key to Creating Electricity from Natural Resources?

  • Thread starter Thread starter Mollz
  • Start date Start date
  • Tags Tags
    Temperature
AI Thread Summary
Temperature is defined as the measure of the average kinetic energy of particles, not their potential energy. There are ongoing efforts to convert thermal energy from molten rock, or magma, into electricity, though the feasibility of this is uncertain. Additionally, the idea of using changes in the specific heat of ocean water to generate electricity is considered false, as specific heat capacity cannot be altered in that manner. The discussion emphasizes the importance of understanding these concepts before seeking assistance. Engaging in multiple threads for the same questions is discouraged to promote learning.
Mollz
Messages
2
Reaction score
0
These are all...true or false? if false- fix.



1)The temp of a material is the total; energy kinetic and potential of its particles.

2)scenarists are working on ways to change the thermal energy of molten rock called magma into electricity .

3)scientists are working on ways to use the change in specific heat of ocean water to make electricity.
 
Physics news on Phys.org
1) FALSE -- I am pretty sure temperature is the measure of the average kinetic energy of the particles not potential.

2) not sure if that possible or not

3) FALSE -- I don't see how you can change the specific heat capacity of water.
 
thank you so much i really appreciate this :-p
 
Mollz, please don't ask your questions in more than one thread. Once again, read the sticky at the top of the thread. Show your work before asking for others to help. This forum is not for other people to do your problem sets for you, but for you to learn how to do it for yourself.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top