Is the Curl of This Vector Field Zero?

mathwizeguy
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Homework Statement


F=-ysin(x)i+cos(x)j


Homework Equations


Can the Curl test be applied to this vector field and state three facts you can deduce after applying the curl test.


The Attempt at a Solution

 
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What exactly do you mean by "curl test"?
 
the curl test is a test to find if a vector field is path independent by taking the partial derivative of F1 and F2 of a function F with respect to x, for F2, and with respect to y, for F1.

Basically I am havin trouble finding 3 facts to incur about this F after the curl test.
 
Are you able to find the curl of this vector field?

In general, if the curl of a vector field is zero, that means that (a) it's the gradient of a scalar (potential) function; and (b) the line integral of scalar potential function is path-independent.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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