Is the Energy Density Formula Applicable to All Capacitors?

  • Thread starter Thread starter Krushnaraj Pandya
  • Start date Start date
  • Tags Tags
    Capacitors
AI Thread Summary
The energy density formula, expressed as Energy density = 1/2 ε₀ E², applies to all capacitors, not just parallel plate capacitors. This formula is valid for any configuration of electric fields. The discussion confirms that the relationship holds true universally in electrostatics. Understanding this principle is essential for analyzing various capacitor types. The formula's applicability emphasizes its significance in electrostatic calculations.
Krushnaraj Pandya
Gold Member
Messages
697
Reaction score
73

Homework Statement


Is the expression Energy density= ## \frac{1}{2} \epsilon_o E^2## true for all capacitors or just parallel plate capacitor?

Homework Equations


all electrostatic related formulas

The Attempt at a Solution


Its just a simple question so...no attempts needed
 
Physics news on Phys.org
Krushnaraj Pandya said:

Homework Statement


Is the expression Energy density= ## \frac{1}{2} \epsilon_o E^2## true for all capacitors or just parallel plate capacitor?

Homework Equations


all electrostatic related formulas

The Attempt at a Solution


Its just a simple question so...no attempts needed
Yes, it is true for electric fields, in general.
 
  • Like
Likes Krushnaraj Pandya
ehild said:
Yes, it is true for electric fields, in general.
Alright, thank you very much.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Comparing energy lost by the battery & energy gained by the capacitor.
Replies
5
Views
2K
Charge on inner/outer surfaces of two large parallel conducting plates
Replies
11
Views
2K
Which quantities are not the same for this capacitor setup?
Replies
5
Views
2K
Potential difference in a 2 disk system (Capacitor)
Replies
4
Views
3K
The energy lost in discharging a capacitor
Replies
16
Views
4K
Electrostatic energy after a metal piece is inserted between 2 capacitor plates
Replies
12
Views
2K
Are ALL parallel plate capacitors linear?
Replies
2
Views
2K
I Thought I Understood Gauss' Law (Sheets)
Replies
26
Views
2K
Capacitor+work energy theorem problem
Replies
18
Views
2K
How Do You Calculate Capacitance in a DC Circuit with a Fully Charged Capacitor?
Replies
3
Views
1K

Hot Threads

Recent Insights

Back
Top