Is the Expectation Value of Uncertainty Constant in Time?

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Homework Statement


Show that, if [H,A] = 0 and dA/dt = 0, then <&Delta;A> is constant in time.


Homework Equations


d<A>/dt = <i/ℏ[H,A] + dA/dt>


The Attempt at a Solution


I am trying to use the above equation to show that d<&Delta;A>/dt is 0, and I can get to d&Delta;A/dt = 0, but I can't figure out how to compute [H,&Delta;A]. The only thing I can think of is that since &Delta; A is just a function of A and A commutes with H, then &Delta; A also commutes with H, but I can't find a theorem that says that.
 
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What's the definition of \delta A ? Then differentiate it wrt time and use Heisenberg's equation of motion.
 
Sorry, I don't know Heisenberg's equation of motion. We haven't gone over it in class and it doesn't show up in my book until much later.
 
What is the name of the equation you placed under <Relevant equations> ?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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