Is the Force Applied to the Ball Zero in this Scenario?

AI Thread Summary
In the scenario of pushing a heavy ball that does not move, the net force acting on the ball is zero, as there is no change in momentum. While an individual is exerting force, the opposing forces may cancel each other out, resulting in zero net force according to Newton's second law. This principle applies similarly to other rigid bodies, such as a building, where the applied force does not result in movement. Although pressure is exerted, it does not equate to a net force causing acceleration. Therefore, while force is being applied, the net force remains zero due to the lack of movement.
Anjum S Khan
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Homework Statement


I am pushing a very heavy ball with full strength, but the ball is not moving at all. So, there is no change in momentum of the ball.
Is it appropriate to say that the Force applied to the ball is zero ?

Homework Equations

The Attempt at a Solution

 
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Anjum S Khan said:

Homework Statement


I am pushing a very heavy ball with full strength, but the ball is not moving at all. So, there is no change in momentum of the ball.
Is it appropriate to say that the Force applied to the ball is zero ?

Homework Equations

The Attempt at a Solution

What are your thoughts on this?
 
Chestermiller said:
What are your thoughts on this?
Force is rate of change of momentum. But here change of momentum is zero, so Force should be zero.
 
Look at it another way. While pushing on the ball, you slip and the ball rolls on top of you and stops. The ball is not moving, yet it is crushing you. Is the force still zero?
 
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SteamKing said:
Look at it another way. While pushing on the ball, you slip and the ball rolls on top of you and stops. The ball is not moving, yet it is crushing you. Is the force still zero?
Change the ball to say some other rigid body which is incompressible anyhow, with very heavy mass. I am pushing it but can't make it move. Then ?
 
Anjum S Khan said:
Change the ball to say some other rigid body which is incompressible anyhow, with very heavy mass. I am pushing it but can't make it move. Then ?
There's a building which you are pushing against. The building does not move, yet your muscles are straining to push it over. Are you exerting no force against the side of this building?
 
Anjum S Khan said:
Change the ball to say some other rigid body which is incompressible anyhow, with very heavy mass. I am pushing it but can't make it move. Then ?
What is the difference between force and net force?
 
SteamKing said:
There's a building which you are pushing against. The building does not move, yet your muscles are straining to push it over. Are you exerting no force against the side of this building?

Of course I am exerting pressure. But in physics terms (Newton's 2nd Law), Force should be zero.
 
Anjum S Khan said:
Of course I am exerting pressure. But in physics terms (Newton's 2nd Law), Force should be zero.
Since pressure is defined as force per unit area, if you are exerting pressure, ipso fatso, you are exerting a force. :wink:
 
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Anjum S Khan said:
Of course I am exerting pressure. But in physics terms (Newton's 2nd Law), Force should be zero.
Newton's 2nd law says that the NET force acting on a body is equal to its mass times acceleration. It doesn't say that any individual force on a body is equal to its mass times acceleration.

If you are pushing on a building (and the building isn't moving), what are the two horizontal forces acting on the building?
 
  • #12
If you are pushing a rigid body and the body doesn't move
It's only so because the "net" force acting on the body equals zero yielding zero acceleration
ΣFexternal = m×a
Where m is the mass and a is the acceleration produced in the body
This is Newton's 2nd Law of motion (simplified)
Look at it in this way
Let's say you're pushing a block on a smooth table and your friend is pushing the block in the opposite direction
Let's say both of you keep on pushing with equal forces but the block doesn't accelerate
Does this mean that you aren't applying a force on the ball?
You are right as you're pushing the ball
However the net force "applied"to the ball is zero as the forces of equal magnitude in opposite directions cancel each other out
Hence it's net force, not an individual force acting on a body which yields the acceleration!

UchihaClan13
 
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