Is the Particle Free? Calculating Equations of Motion

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Homework Statement



The one-dimensional motion of a particle with coordinate q is governed by the Lagrangian

L = (dq/dt)2(6q2 - 4qt(dq/dt) + (dq/dt)2t2)

Show that the particle must be free

Homework Equations





The Attempt at a Solution



I know that L needs to depend only on (dq/dt)2 for the particle to be free, but I don't know how to do it...
 
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One way to show that it is a free particle (i.e., there are no forces on it) is to calculate the equations of motion...if \ddot{q}=0[/itex], then Newton's second law tells you the net force on the particle is everywhere zero.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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