Is the Period of a Charged Particle in a Magnetic Field Speed-Dependent?

AI Thread Summary
The discussion focuses on proving that the period of a charged particle moving perpendicular to a uniform magnetic field is independent of its speed. Participants are tasked with deriving an expression for the period T based on the particle's mass, charge, and the magnetic field strength. The relationship between centripetal force and magnetic force is highlighted, leading to the need to express the period without involving radius or velocity. A suggestion is made to derive the period from the circular motion formula to eliminate these variables. The conversation emphasizes the importance of correctly formulating the period in terms of the relevant physical quantities.
soul5
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Homework Statement


Prove that the time for one revolution of a charged particle moving perpendicular to a uniform magnetic field is independent of it's speed. Write an expression that gives the period T in terms of the mass and charge of the particle and the magnetic field strength.


Homework Equations



Fc=4*pi*^2mr/T^2

Fm=qvB



The Attempt at a Solution



Fc=Fm

v=4*pi*^2mr/T^2qB

is that right?
 
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Hi soul5,

You're expressions look like they are true, but they don't answer the question. The question asks for the expression for the period, but that expresion is not supposed to have r and v in it.

If you can find a formula for the period in terms of r and v you can use that to eliminate r and v in your equation.

So let's say you have an object moving at speed v in a circular path of radius r. What is the period (time to go once around the circle)? Once you have that, use it to eliminate r and v. What do you get?
 
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