Is the Set of Polynomials of Degree ≤ 6 with a3 = 3 a Vector Space?

kq6up
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Homework Statement



For each of the following sets, either verify (as in Example 1) that it is a vector space, or show which requirements are not satisfied. If it is a vector space, find a basis and the dimension of the space.

6. Polynomials of degree ≤ 6 with a3 = 3.

Homework Equations



N/A

The Attempt at a Solution



I put that it was a vector space with the basis of {1,x,x^2,3*x^3,x^4,x^5,x^6} and dimension of 7. I am not sure why it fails to be a vector space.

Chris
 
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What happens if you add two members of the given set, or if you multiply a member by a scalar?
 
I think there is a closure problem because one would not be able to get rid of the 3*x^3 by playing with coefficients.

I will have to think about it a little more.

Chris
 
kq6up said:
I think there is a closure problem ##\ldots##
Definitely.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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