Is the solution correct? (forces between 3 charged particles)

AI Thread Summary
The discussion centers on the interpretation of "total" force in the context of three charged particles. It emphasizes that "total" should be understood as the vector sum of forces rather than merely the sum of their magnitudes. The correct calculation of the resultant force, particularly the x-component, is crucial for determining instantaneous acceleration. Additionally, the conversation critiques the misrepresentation of vector forces in educational materials, highlighting the importance of vector addition in physics. The lack of units in the example provided is also noted as a significant oversight.
PhysicsTeacher159
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Homework Statement
Three charges are arranged in a li ne with 2.5 cm between them, as shown in Figure 2.33. What is the force exerted on a Charge 2 by the other two charges?
Relevant Equations
Coulomb's law
Example2.7page66Physics10thgrade.png
 
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Well it depends on what you mean by "total". If you define "total" to be the sum of the magnitudes, then it's fine. But that definition is not really helpful, for anything. It's certainly not how I would interpret it.

It's much more common for "total" to mean the vector sum, or equivalently if you write those vectors in terms of a basis, the sum of the components of a particular basis vector.

In that case, if you for instance let the ##\hat{x}## basis vector point to the right, the ##x##-component of the resultant force is going to be ##F_x = F_{12} - F_{32}##. This is now a useful quantity, which you can use to e.g. determine the instantaneous acceleration.
 
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Thanks.
 
Does the worked example come from an "official" book? I can't believe how the "author" ignores the vector nature of forces.
 
PhysicsTeacher159 said:
Thanks.
To add to what @etotheipi said: if the forces ##F_{12}## and ##F_{32}## were equal and opposite, then the total force on ##q_2## would definitely be zero. You definitely need a minus sign.

Note that the electric field is what determines the force on ##q_2##. There is no sense in which you can add the magnitude of electric fields - they must be added vectorially.
 
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I am reminded of the chapter from "Surely Your Joking..." where Prof Feynman is approving high school texts for the school board and one problem asks for the sum of the temperatures of four stars. Equivalently cringeworthy calculation.
 
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The directions of the arrows representing F12 and F32 are correctly drawn but with their tips at the charge instead of their tails. Grasping at straws, I can hypothesize how one might look at the drawing and erroneously conclude that since one charge "squeezes" q2 from the left and the other squeezes from the right, charge q2 is squozen from both sides with a "total" force that is the sum of the two forces because it should be a harder squeeze than if either force alone acted on the charge. Something like that but still indicative of poor understanding of what a net force and Newton's 2nd are all about.

I also lament the lack of units in the answer.
 
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