Is there an easier way to do this integral?

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\int_{-1}^1 x^8\sin x dx

I know I can do this using integration by parts. But I'd have to do integration by parts 8 times and since I plan on passing calc 2 at the end of this semester I need a quicker way.:smile:

If anyone has any hints for me or anything please post them. Thank you for your help.
 
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I notice that it is a definite integral. If you know what kind of function this is, there is a real shortcut..
 
As Hammie said, it's often helpful to understand your function! Have you tried anything like plotting it?
 
AHHHHHHH! sin(x) is odd! The area under the graph of this function between 1 and -1 is 0! Thanks alot.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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