Is This a Long or Short Rossby Wave at 35o N?

geojon
Messages
19
Reaction score
0

Homework Statement


Consider a Rossby wave propagating in a homogeneous ocean with a water depth of 4,000m at 35o N latitude. If the wave length of this wave is 500km, is this a long or short Rossby wave?

Homework Equations


shortwaves: |kx-1| <<RD
longwaves: |kx-1| >> RD

kx is the x-component of the wave number, k. wavenumber = 2pie/λ
-kx = k

RD = Rossby Radius of Deformation = (gh)1/2 / ƒ
where ƒ is the Coriolis parameter.

The Attempt at a Solution


RD = Rossby Radius of Deformation = (gh)1/2 / ƒ = 2.38 x 106m. ƒ is in seconds-1, RD is in meters.

-kx = k = 2Pie / λ. = 1.26 x 10-5 rad m-1.

I want to compare |kx-1| to RD. How do I change my units for kx?? Because I cannot compare something in rad*m-1 to meters.

I think that I have to change the radians to a distance, using the Earth's radius (6,371 km), at a latitude of 35o North. This is where I am stumped??
 
Physics news on Phys.org
One radian on the Earth = 1 Earth radius in length right?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top