Is This Calculation of Heat Engine Efficiency Correct?

  • Thread starter Thread starter needhelp83
  • Start date Start date
AI Thread Summary
The calculation for the efficiency of the heat engine is confirmed as correct, yielding an efficiency of 32%. The formula used is e = W/Q_h, where W is the useful work and Q_h is the heat produced. The values provided were 2700 J of work and 8500 J of heat. The simplicity of the problem raised some initial doubts, but the calculation stands validated. Overall, the efficiency calculation is straightforward and accurate.
needhelp83
Messages
193
Reaction score
0
A heat engine produces 8500 J of heat while performing 2700 J of useful work. What is the efficiency of this engine?

e=W/Q_h =2700 J/8500 J =0.32 or 32%


This just looked way to easy...hoping to have someone double check
 
Physics news on Phys.org
Sounds good.
 
Wow, what an easy problem. Thanks for the help
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top