Is this right? (trig equation)

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Byrgg
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It's set up like this and you have to solve for all possible angles:

-360 degrees <= theta <= 360 degrees

8cos ^ 2 theta + 7cos theta - 1 = 0

(my work)

(8cos - 1)(cos theta + 1) = 0

8cos theta - 1 = 0
8cos theta = 1
cos theta = 1/8
theta = 1/8 cos ^ -1

theta = 83 degrees
= -83 degrees
= 277 degrees
= -277 degrees

OR

cos theta + 1 = 0
cos theta = -1
theta = -1cos ^ -1

theta = 180 degrees
= -180 degrees

The back of the textbook has only the answers before my "OR", they do not show the possible 180 and -180 degrees that I calculated, did they just forget or did I mess something up?
 
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They must have left them out--your answers are correct. You can verify that those answers are correct by plugging them back into the original equation.
 
Ok thanks for your time, it not's the first time I've encountered incorrect(or in this case exclusive) answers in a textbook, just wanted to make sure.
 
Actually there's one more, would you mind helping me?
 
Never mind I just figured it out, I accidentally wrote 4/2 * 1 = 1 instead of 2

I got the right answer after that correction, thanks anyways.