Is This System Time Invariant?

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SUMMARY

The system defined by the equation y(n) = x(4n + 1) is not time invariant, as established by the professor's correction of the student's homework. Time invariance requires that a shift in the input results in an equivalent shift in the output. The student's attempt to demonstrate time invariance through the equations y1 = x(4(n - n0) + 1) and y2 = y(n - n0) = x(4(n - n0) + 1) fails because the output shift results in a factor of -4T instead of the expected -T. This discrepancy confirms the system's lack of time invariance.

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Homework Statement



y(n)=x(4n+1). Is this system T.I or NOT T.I

The professor marked this question wrong for my homework. He says it's NOT time invariant. I proved it is time invariant.

Homework Equations



System is time invariant if a shift in time in input results in the same shift in time when the output is shifted.

The Attempt at a Solution


shift in the x:
y1=x(4(n-n0)+1)
y2=shift in y=y(n-n0)=x(4(n-n0)+1)

They are the same, therefore they system is time invariant.
The professor marked this problem wrong for me, and he gave me the run-around when I asked for him to prove it. Did I do this right?
 
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