In the equation x = vt it is generally accepted that x and v are vectors and that they have a common eigenvector. Each vector is the product of a scalar and a unitary eigenvector. Dividing both sides by v works because in x/v = t the x and v vectors have identical and canceling eigenvectors. This would indicate then that t is the quotient of two scalar values, yielding a scalar value. If t is a vector then the multiplication of v and t doesn't work and the division of x/v doesn't work. Flat Minkowski space has a matrix of: | x 0 0 0 | - - - | 1 0 0 0 | | 0 y 0 0 | or - | 0 1 0 0 | | 0 0 z 0 | - - - | 0 0 1 0 | | 0 0 0 -ct | - - | 0 0 0 -c | This standard matrix is composed of vectors. Since x, y, z are vectors then -ct must also be a vector. The speed of light (c) is a scalar therefore t must be a vector for this matrix. Yet, the previous discussion indicates that t must be a scalar? Is Time (t) a vector or a scalar? If t is a scalar then there can be no time travel?