- #1
eljose79
- 1,518
- 1
let suppose we have two observables A and B so its conmutator [A,B]=f(p,q)
then let,s define a new observable C so [A,BC]=0 so we could measure A and BC with C a function of (q,p)the statement above is equivalent to (A,BC)=0 with () the Poisson Bracket then let,s put A=q and B=p then we must have [x,pC]=0 so we now can meassure x and pc with c is a function g(q,p) then c=g(q,p) inverting we have g^-1(c,q)=p so we can meassure p.
then let,s define a new observable C so [A,BC]=0 so we could measure A and BC with C a function of (q,p)the statement above is equivalent to (A,BC)=0 with () the Poisson Bracket then let,s put A=q and B=p then we must have [x,pC]=0 so we now can meassure x and pc with c is a function g(q,p) then c=g(q,p) inverting we have g^-1(c,q)=p so we can meassure p.