Is Work Always the Transfer of Energy?

  • Thread starter Thread starter curiously33
  • Start date Start date
  • Tags Tags
    Energy Work
AI Thread Summary
Work is defined as a force acting over a distance, and it can occur even without direct contact, as seen with a soccer ball in motion. The ball possesses kinetic energy when kicked, which converts to gravitational potential energy as it rises, while some energy is lost to heat due to air friction. Potential energy is not merely a concept; it has tangible effects depending on the reference point, such as a brick on a roof having potential energy relative to the ground but not to the roof. Kinetic energy also varies based on the observer's motion, emphasizing the relativity of energy measurements. Ultimately, work is the mechanism that facilitates changes in energy states.
curiously33
Messages
2
Reaction score
0
Is work always the transfer of energy?

This wasn't in any homework, but I've tried asking various teachers and searching the internet, and I can't find any definitive answer. I'm currently learning about work in Grade 11 Physics, and I was wondering. I know that work is a force acting over a distance, but if a soccer ball, for example, is traveling through the air, there is no contact, and therefore no transfer of energy. However, work is still being done. I know that it has kinematic energy due to it's motion, but there is no transfer of energy.
 
Physics news on Phys.org
There is transfer of energy. The ball will initially have kinetic energy as it is kicked. As it rises through the air, some of that energy is converted into gravitational potential energy and some is converted to heat (due to friction with the air it is moving through).
 
Oh. I see. Thank you for the clarification. Another question: I thought potential energy was just a concept rather than an actual property. Is that not the case?
 
curiously33 said:
Oh. I see. Thank you for the clarification. Another question: I thought potential energy was just a concept rather than an actual property. Is that not the case?
Change in potential energy is what is important, but that still does not imply that potential energy by itself is just a concept. A brick on a roof has potential energy with respect to the ground, but none with respect to the roof. But you can say the same thing about kinetic energy: a moving object has kinetic energy with respect to a stationary observer, but has no kinetic energy with respect to an observer moving at the same speed as the object. In both cases, however, it is work that causes the change in energy. Its all relative, you know.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top