Is Z7[x] Isomorphic to Z?

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Homework Statement



Let R = Z7[x]. Show that R is not isomorphic to Z.

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The Attempt at a Solution



One of the necessary conditions for an isomorphism f is that f be one to one. So consider 8x in Z. f(8x) = x, f(1x) = x. So f cannot be an isomorphism. I'm clearly missing something though, since this seems a bit too easy.
 
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Actually nevermind, it is that easy. There's a hint hidden that basically says "an isomorphism has to be one to one..."
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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